Question

Player Aled a baseball league in runs batted in for the 2005 regular season. Player B, who came in second to player A, had 18 fewer runs batted in for the 2005 regula
season. Together, these two players brought home 232 runs during the 2005 regular season. How many runs batted in did player A and player Beach account for?
Player A had
runs and player B had
runs batted in for the 2005 regular season.

Answer 1

Answer:

A = 120

B = 102

Step-by-step explanation:

Assume A had x runs

So B had $x-18$ runs {the total runs is 222}

A + B = 222

2x = 240

x = 120

B: x - 18 = 120 - 18 = 102