Using the vertex of the quadratic function, it is found that his maximum profit is of $75 when he charges $15 for a key-chain.
What is the vertex of a quadratic equation?
A quadratic equation is modeled by:
[tex]y = ax^2 + bx + c[/tex]
The vertex is given by:
[tex](x_v, y_v)[/tex]
In which:
[tex]x_v = -\frac{b}{2a}[/tex]
[tex]y_v = -\frac{b^2 - 4ac}{4a}[/tex]
Considering the coefficient a, we have that:
- If a < 0, the vertex is a maximum point.
- If a > 0, the vertex is a minimum point.
In this problem, the function is:
[tex]f(x) = (x - 10)(60 - 3x)[/tex]
In standard format, it is given by:
[tex]f(x) = -3x^2 + 90x - 600[/tex]
Which means that it's coefficients are a = -3, b = 90, c = -600.
Hence:
[tex]x_v = -\frac{90}{2(-3)} = 15[/tex]
[tex]y_v = -\frac{90^2 - 4(-3)(-600)}{4(-3)} = 75[/tex]
Hence, his maximum profit is of $75 when he charges $15 for a key-chain.
More can be learned about the vertex of a quadratic function at https://brainly.com/question/24737967