20.0 moles of O₂ react with Sb to form 13.3 moles of Sb₂O₃.
We want to calculate how many moles of Sb₂O₃ will be formed from 20.0 moles of O₂. This is a stoichiometry problem.
Stoichiometry is the relationship between the relative quantities of substances taking part in a reaction or forming a compound, typically a ratio of whole integers.
4 Sb + 3 O₂ ⇒ 2 Sb₂O₃
The molar ratio of O₂ to Sb₂O₃ is 3:2.
20.0 mol O₂ × (2 mol Sb₂O₃/3 mol O₂) = 13.3 mol Sb₂O₃
20.0 moles of O₂ react with Sb to form 13.3 moles of Sb₂O₃.
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