Question

ILL Give Brainiest, A bag contains 11 numbered chips inside. Two chips are labeled 1, three are labeled 2, and six are labeled 3. Let the random variable X = "number on a chip in the bag."
What is the expected number of a chip that is randomly chosen from the bag?

µ = 3.87
µ = 1.54
µ = 2.36
µ = 5.57

Answer 1

The expected value of the discrete distribution is given by:

µ = 2.36

What is the expected value of a discrete distribution?

It is given by the sum of each value multiplied by it's respective probability.

In this problem, the distribution is as follows, considering the amounts of each chip:

P(X = 1) = 2/11

P(X = 2) = 3/11

P(X = 3) = 6/11

Hence, the expected value is given by:

$\mu = \frac{2}{11} + 2\frac{3}{11} + 3\frac{6}{11} = \frac{2 + 6 + 18}{11} = 2.36$

More can be learned about the expected value of a discrete distribution at https://brainly.com/question/24855677