Question

What is the equilibrium concentration of substance A given that Kc = 4.0 x 10–2? Here is the reaction: 2A ⇌ B + C The initial concentration of A is 1.7 M, the initial concentration of B is 0.2 M and the initial concentration of C is 0.2 M.

Answer 1

We have that the concentration of a  is mathematically given as

A=1.584

Concentration  of A

Question Parameters:

given that Kc = 4.0 x 10–2? Here is the reaction: 2A ⇌ B + C

The initial concentration of A is 1.7 M,

the initial concentration of B is 0.2 M and

the initial concentration of C is 0.2 M.

Generally the equation for the Equilibrium constant  is mathematically given as

$Kc=\frac{BC}{A^2}\\\\Therefore\\\\4e-2=\frac{x^2}{(1.9-x)^2}$

x=0.316

A=1.9-x

A=1.9-0.316

A=1.584

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