Question

Please help im close to failing it would mean the world

Answer 1

$\\ \rm\hookrightarrow (3^8.2^{-5})^{-2}(2^{-2}3^{-3})^4.3^{28}$

$\\ \rm\hookrightarrow 3^{-16}

.2^{-10}.2^{-8}.3^{-12}>3^{28}$

$\\ \rm\hookrightarrow 3^{-16-12+28}2^{-10-8}$

$\\ \rm\hookrightarrow 3^02^{-18}$

$\\ \rm\hookrightarrow \dfrac{1}{2^{18}}$