Question

A well can pump 800L of gas in25 minutes .How much gas can it pump in 2 hours ?

Answer 1

answer:

3840 L of gas can be pumped in 2 hours.

explanation:

2 hours = 120 minutes

solve:

25 minutes → 800 L

1 minutes → 800/25

1 minutes → 32 L

then in 2 hrs or 120 minutes:

120  minutes → ( 32 * 120 ) L

120 minutes → 3840 L

or by basic calculations:

$\frac{800}{25} * 120$  → 3840 L

Answer 2

Given :-

• A well can pump 800L of gas in 25min .

To Find :-

• How much gas it can pump in 2 hrs.

Solution :-

Firstly we know that ,

1hr = 60min , so,

2hrs = 60*2 = 120 min

Here we can use the Unitary Method as ,

In 25min 800L of gas can be pumped .

In 1min 800/25 L of gas can be pumped.

In 120min 800/25 *120 L = 3840L of gas can be pumped .

Hence the required answer is 3840 L .