Help me out again lovely geniuses.

Solution:
Since the triangles are similar:
Solving the equation:
The value of x is 12.
[tex]\\ \tt\hookrightarrow \dfrac{9}{x}=\dfrac{9+6}{20}[/tex]
[tex]\\ \tt\hookrightarrow \dfrac{9}{x}=\dfrac{15}{20}[/tex]
[tex]\\ \tt\hookrightarrow \dfrac{9}{x}=\dfrac{3}{4}[/tex]
[tex]\\ \tt\hookrightarrow 3x=36[/tex]
[tex]\\ \tt\hookrightarrow x=12[/tex]