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Answer:

[tex]\rm {6a}^{3} b - 12 {a}^{4} b + 15 {a}^{3} {b}^{2} - {3a}^{2} {b}^{2} \: by \: {3a}^{2} b[/tex]

[tex] \rm\displaystyle\frac{6 \times a \times a \times a \times b}{3 \times a \times a \times b} - \frac{12 \times a \times a \times a \times a \times b}{3 \times a \times a \times b} + \frac{15 \times a \times a \times a \times b \times b}{3 \times a \times a \times b} -\frac{3×a×a×b×b}{3×a×a×b}[/tex]

[tex] \rm\displaystyle\frac{ \cancel6 {}^{2} \times \cancel a \times \cancel a \times a \times \cancel b}{ \cancel3 \times \cancel a \times \cancel a \times \cancel b} - \frac{ \cancel{12 }^4\times \cancel a \times \cancel a \times a \times a \times \cancel b}{ \cancel3 \times \cancel a \times \cancel{a }\times \cancel{b}} + \frac{ \cancel{15 }{}^{3} \times \cancel a \times \cancel a \times a \times \cancel b \times b}{ \cancel3 \times \cancel{a} \times \cancel a \times \cancel b}-\frac{\cancel{3}×\cancel{a}×\cancel{a}×\cancel{b}×b}{\cancel3×\cancel{a}×\cancel{a}×\cancel{b}} [/tex]

[tex]\rm2 \times a - 4 \times a \times a \: +3 \times a \times \: b-b[/tex]

[tex]\rm2a - 12a^3b-b[/tex]

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