A wallet contains five $10 bills, four $5 bills, and six $1 bills (nothing larger). If the bills are selected one by one in random order, what is the probability that at least two bills must be selected to obtain a first $10 bill?.
So this is what I did I added all the values: 5+4+6=15 and there are 5 $10 bills, so it would be 5/15, or simplified, 1,3, I hope this answer helps, I tried my best
