Question

A spring has a natural length of 30.0 cm. If a 22.0-N force is required to keep it stretched to a length of 34.0 cm, how much work W is required to stretch it from 30.0 cm to 32.0 cm

Answer 1

Answer:

0.11 J

Explanation:

First, find the spring constant k:

k = 22.0 / (0.340 - 0.300) = 550 N/m

W = change of kx^2/2

W = (1/2) * 550 * (0.320 - 0.300)^2 = 0.11 J