Question

Please help!
An archer uses an average force of 50.0 N to draw the
string of his bow through a distance of 0.412 m. Then,
he fires a 297 g arrow straight up into the air.
What is the maximum speed of the arrow at the instant it leaves the bow?

Answer 1

Answer:

$mgh=Fs$ \\

$(0.297)(9.8)h = (50)(0.412)$

$h = 7.08m$

Explanation:

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Answer 2

The maximum speed of the arrow at the instant it leaves the bow is 8.34m/s

Force and velocity

The formula for calculating force is expressed as

F = ma

F = mv²/r

Given the following

Force = 50N

radius r = 0.412m

m = 297g = 0.297kg

Required

maximum  speed

Substitute into the formula to have:

F = mv²/r

50 = 0.297*v²/0.413

v = 8.34 m/s

Hence the maximum speed of the arrow at the instant it leaves the bow is 8.34m/s

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