A, B & C form the vertices of a triangle, where

CAB = 90°.
AB = 5.9 m and BC = 11.1m.
Evaluate

ABC, giving your answer rounded to 3 SF.

Respuesta :

Answer:

57.9°

Step-by-step explanation:

Sine rule

SinA/a = SinB/b to find angle BCA

Sin90/11.1 = Sinx/5.9 make sinx the subject

Sin90/11.1 × 5.9 = sinx

X=32.10899276

Angles in a triangle add up to 180°

So 32.10899276+90+y=180

180-122.1089928=57.89100724

Angle ABC=57.9°

A triangle is a shape with 3 sides and angles. The measure of angle ∠ABC is 57.6 degrees

Application of trigonometry identity

A triangle is a shape with 3 sides and angles. Given the following parameters

∠CAB = 90°.

AB = 5.9 m and;

BC = 11.1m.

Determine the measure of ∠ABC

cos∠ABC = AB/BC
cos∠ABC = 5.9/11

cos∠ABC = 0.5363

∠ABC = arccos0.5363

∠ABC = 57.6 degrees

Hence the measure of angle ∠ABC is 57.6 degrees

Learn more on angles here: https://brainly.com/question/25716982

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