In a class of 26 students, 15 of them like maths,
13 of them like english and 9 of them don’t like Maths or English
Find the probability that a student chosen at random
likes English but not Maths.

Respuesta :

Answer:

2/13

Step-by-step explanation:

Easiest way is to draw a Venn diagram

If there are a total of 26 students and 9 of the students don't like Maths or English, then 26 - 9 = 17 students like Maths or English or both

Let m = the number of students who like Maths only

Let e = the number of students who like English only

Let a = the number of students who like BOTH

From the given information:

m + b = 15   ⇒  b = 15 - m

e + b = 13

m + e + b = 17

Substitute  b = 15 - m  into  m + e + b = 17:

⇒ m + e + 15 - m = 17

⇒ e + 15 = 17

⇒ e = 2

Substitute  e = 2  into  e + b = 13:

⇒ 2 + b = 13

⇒ b = 11

Substitute b = 11  into  m + b = 15:

⇒  m + 11 = 15

⇒  m = 4

Now you can draw a Venn diagram (see attached diagram).

Reading from the Venn diagram, the probability that a student likes English but not Maths is 4/26 = 2/13

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