Consider the equation y = a - bx. If y = 6 when x = 1 and y = 0 when x = 2, find . = х
(a) the value of a and b
(b) the value of y when x = 4.​

Consider the equation y a bx If y 6 when x 1 and y 0 when x 2 find х a the value of a and bb the value of y when x 4 class=

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Answer:

see explanation

Step-by-step explanation:

(a)

y = [tex]\frac{a}{x}[/tex] - bx

substitute y = 6 , x = 1 into the equation

6 = a - b → (1)

substitute y = 0 , x = 2 into the equation

0 = [tex]\frac{a}{2}[/tex] - 2b ( multiply through by 2 to clear the fraction )

0 = a - 4b → (2)

multiply (1) by - 4

- 24 = - 4a + 4b → (3)

add (2) and (3) term by term to eliminate b

- 24 = - 3a + 0

- 24 = - 3a ( divide both sides by - 3 )

8 = a

substitute a = 8 into (1) and solve for b

6 = 8 - b ( subtract 8 from both sides )

- 2 = - b ( multiply both sides by - 1 )

2 = b

Then a = 8 and b = 2

(b)

when x = 4

y = [tex]\frac{8}{4}[/tex] - 2(2) = 2 - 4 = - 2

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