Question

Find the limit of the function shown below (a) as x → ∞ and (b) as x → - ∞

Answer 1

Step-by-step explanation:

$\lim_{x \to \infty} \frac{3-\frac{2}{x} }{4+\frac{\sqrt{2}}{x^2}}= \lim_{x \to \infty} \frac{3-0}{4+0}=\frac{3}{4}(-).$

$\lim_{x \to- \infty} \frac{3-\frac{2}{x}}{4+\frac{\sqrt{2}}{x^2}}= \lim_{x \to- \infty}\frac{3-0}{4+0}=\frac{3}{4}(+).$

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