The equation of the rotating light is an illustration of a secant function
The equation that represents the distance between the center of the circle and the light source is [tex]d(t) = 40\sec(\frac{\pi}{3}t)[/tex]
The equation is a secant function represented by
[tex]y =A\sec(Bt)[/tex]
Where:
A represents the amplitude
So, we have:
[tex]A = 40[/tex] --- the distance of the light from each square wall
B represents the period, and it is calculated as:
[tex]B = \frac{2\pi}{T}[/tex]
The light completes its full rotation every 6 seconds.
This means that,
T = 6
So, we have:
[tex]B = \frac{2\pi}{6}[/tex]
Simplify
[tex]B = \frac{\pi}{3}[/tex]
Substitute values for A and B in [tex]y =A\sec(Bt)[/tex]
[tex]y = 40\sec(\frac{\pi}{3}t)[/tex]
Rewrite as a function
[tex]d(t) = 40\sec(\frac{\pi}{3}t)[/tex]
Hence, the equation that represents the distance between the center of the circle and the light source is [tex]d(t) = 40\sec(\frac{\pi}{3}t)[/tex]
Read more about trigonometry functions at:
https://brainly.com/question/1143565