a strobe light is located at the center of a square dance room. the rotating light is 40 feet from each of the square walls and complete 1 full rotation every 6 sec.
a) write an equation, representing the distance, d, in feet that the center of the circle of light, is a light source at t time.

Respuesta :

The equation of the rotating light is an illustration of a secant function

The equation that represents the distance between the center of the circle and the light source is [tex]d(t) = 40\sec(\frac{\pi}{3}t)[/tex]

How to determine the equation

The equation is a secant function represented by

[tex]y =A\sec(Bt)[/tex]

Where:

A represents the amplitude

So, we have:

[tex]A = 40[/tex] --- the distance of the light from each square wall

B represents the period, and it is calculated as:

[tex]B = \frac{2\pi}{T}[/tex]

The light completes its full rotation every 6 seconds.

This means that,

T = 6

So, we have:

[tex]B = \frac{2\pi}{6}[/tex]

Simplify

[tex]B = \frac{\pi}{3}[/tex]

Substitute values for A and B in [tex]y =A\sec(Bt)[/tex]

[tex]y = 40\sec(\frac{\pi}{3}t)[/tex]

Rewrite as a function

[tex]d(t) = 40\sec(\frac{\pi}{3}t)[/tex]

Hence, the equation that represents the distance between the center of the circle and the light source is [tex]d(t) = 40\sec(\frac{\pi}{3}t)[/tex]

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