Question

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4x+3/x + 24/2x^2−8x

Answer 1

$\\ \tt\hookrightarrow 4x+\dfrac{3}{x}+\dfrac{24}{2x^2}-8x$

$\\ \tt\hookrightarrow 4x-8x+3/x+1/x^2$

$\\ \tt\hookrightarrow -4x+3/x+1/x^2$

$\\ \tt\hookrightarrow \dfrac{-4x^2+3}{x}+\dfrac{1}{x^2}$

$\\ \tt\hookrightarrow \dfrac{-4x^3+3x+1}{x^2}$

Answer 2

Answer:

(-4x^3+3x+12)/x^2

Step-by-step explanation:

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