[tex] \huge \sf \dag \: Answer : [/tex]
[tex] \longmapsto \rm 2x + 6x + 10 = 0[/tex]
[tex] \longmapsto \rm 8x = - 10[/tex]
[tex] \longmapsto \sf x = - \frac{10}{8}[/tex]
Because this is just an ordinary linear equation and only has 1 value of x that meets it, it can be concluded that the value of [tex]\tt x_1[/tex] is equal to [tex]\tt x_2[/tex], then:
[tex] \longmapsto \sf x_2 + x_2[/tex]
[tex] \longmapsto \sf ( - \frac{10}{8} ) + ( - \frac{10}{8} )[/tex]
[tex] \longmapsto \sf \boxed{\boxed{ \bf{ - \frac{20}{8}}} }[/tex]
-I Hope This Helps!!
