Question

factoring by grouping

x^2 + 4y + 2x + 2xy
pls explain with work too!!!

Answer 1

${x}^{2} + 4y + 2x + 2xy$

We can factorise this expression by grouping. First let us arrange it in this way

$= {x}^{2} + 2xy + 2x + 4y$

Let us bracket them like this:

$= ( {x}^{2} + 2xy) + (2x+ 4y)$

In the first bracket portion, take x as common and in the second expression, take 2 as common.

$= x(x + 2y) + 2(x + 2y) \\ = (x + 2)(x + 2y)$

Answer:

$(x + 2)(x + 2y)$

Hope you could understand.

If you have any query, feel free to ask.

Answer 2

$\tt \: {x}^{2} + 4y + 2x + 2xy$

Factor out x from the expression

$\tt \: x \times (x + 2) + 4y + 2xy$

Factor out 2y from the expression

$\tt \: x \times (x + 2) + 2y \times (2 + x)$

Factor out x+2 from the expression

$\boxed{ \sf \: (x + 2) \times (x + 2y)}$

➪ Therefore, The factors are: (x+2) & (x+2y)