Find the surface area of the cylinder in terms of pi
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Answer:
A≈301.44
Step-by-step explanation:
The area of a cylinder is A=2πrh+2πr^2
You first do the first problem of the equation (A=2πrh)
You fill in the radius and height ( A=2π(4)(8) )
You first multiply 4 x 8 = 32. ( A=2π(32) )
Then you multiply 2 x 32 = 64. ( A=π(64) )
Then you multiply π x 64 (using 3.14 for π) = 200.96 m^2
You then do the second part of the equation. (A=2πr^2)
You fill in the radius. (A=2π(4)^2)
Then multiply 4 x 4 = 16 (because it's to the power of 2 [4 times itself twice]) and then multiply it by 2.
16 x 2 = 32. ( A=π(32) )
Next you just multiply 32 x π (using 3.14 for π again) = 100.48 m^2.
Then you just add them together:
200.96 m^2 + 100.48 m^2 = 301.44 m^2
So 301.44 m^2 is your answer.
(I hopefully think it is.)
Answer:
96π
Step-by-step explanation:
SA= 2πRH+2πR^2
R=4
H=8
2π4(8)+ 2π4^2
2π32+2π16
multiply 2*32 and 2*16
64π+32π add them together
SA= 96π