Question

A rope is being pulled with a force of 366 N parallel to the horizontal surface right, five men are pulling the same rope parallel to the horizontal surface but toward left. what amount of force should an individual apply towards left to keep the rope in equilibrium (suppose that each of five men is contributing same force)

Answer 1

The amount of force applied by individual man to balance the force at the right is 73.2 N.

Amount of force applied by individual man

The amount of force applied by individual man to balance the force at the right is calculated as follows;

$F_{right} = F_{left}\\\\F_{left} = F_1 + F_2 + F_3 + F_4 + F_5\\\\F _1 = F_2 = F_3 = F_4 = F_5\\\\F_1 = \frac{F_{right}}{5} = \frac{366}{5} = 73.2 \ N$

Thus, the amount of force applied by individual man to balance the force at the right is 73.2 N.

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