Answer: 2/4 (or 1/2, simplified)
Explanation:
The question is asking the probability of the flower positions being heterozygous (meaning having both the axial AND terminal alleles). Since the Punnett square is already solved, you can see that there are TWO out of FOUR different possibilities that have both the axial (F) and terminal (f) alleles, which would be the heterozygous alleles that the question is asking about. Since there are two heterozygous plants out of the four listed, the answer would be 2/4 as the final answer. Hope that helps :)
