Question

Abby feeds her dog 1 1/2 cups of food each day, and Braxton feeds his dog 4 1/2 cups of food each day. In one week, how many times more dog food does Braxton’s dog eat when compared with Abby’s dog?

Braxton’s dog eats 5 times more food.
Braxton’s dog eats 3 times more food.
Braxton’s dog eats 4 times more food.
Braxton’s dog eats 2 times more food.

Answer 1

Solution:

Note that:

• Abby's dog: 1.5 cups of food
• Braxton's dog: 4.5 cups of food

Looking at the information we got, we can say that Braxton's dog eats more. Let's put them into ratio form (Braxton's dog:Abby's dog)

• => (Braxton's dog:Abby's dog) = 4.5:1.5

Now, put them into fractions.

• => 4.5:1.5 = 4.5/1.5 = 3

We can conclude that Braxton's dog eats 3 times more food.

Answer 2

• Abby's dog eats each day=1 1/2=3/2=1.5cups
• Braxtons dog eats each day=4 1/2=9/2=4.5cups

Find ratio

$\\ \tt\hookrightarrow \dfrac{4.5}{1.5}=3$

Braxtons dog eats 3times more than Abbys