Question

If 12.4 grams of O, are used, how many grams of CH, are also used?
(O2 has molar mass 32.0 g/mol)

Answer 1

Answer: the balanced equation for the reaction between Mg and O₂ is as follows

2Mg + O₂ --> 2MgO

stoichiometry between Mg and O₂ is 2:1

number of Mg reacted - 4.00 mol

if 2 mol of Mg reacts with 1 mol of O₂

then 4.00 mol of Mg requires - 1/2 x 4.00 = 2.00 mol of O₂

then the mass of O₂ required - 2.00 mol x 32.0 g/mol = 64.0 g

64.0 g of O₂ is required for the reaction

Explanation: