Question

20 points please answer quick

Answer 1

Answer:

$x^8\sqrt[3]{x}$

Step-by-step explanation:

$\sqrt[3]{x^{25}}$

Apply the exponent rule $a^{b+c}=a^b \cdot a^c$

$\implies \sqrt[3]{x^{(24+1)}}=\sqrt[3]{x^{24}x^1}=\sqrt[3]{x^{24}x}$

Apply the radical rule $\sqrt{ab} =\sqrt{a}\sqrt{b}$:

$\implies =\sqrt[3]{x^{24}x}=\sqrt[3]{x^{24}}\sqrt[3]{x}$

Apply the radical rule $\sqrt[a]{x^b} =x^{\frac{b}{a}}$:

$\implies \sqrt[3]{x^{24}}\sqrt[3]{x}=x^{\frac{24}{3}}\sqrt[3]{x}=x^8\sqrt[3]{x}$