Question

How do I solve this? y = 4 Log x + 5

Answer 1

Answer:

$x=10^{\frac14(y-5)}$

Step-by-step explanation:

$y = 4 log (x) + 5$

$\implies y - 5 = 4 log(x)$

$\implies \dfrac14(y-5)=log(x)$

Using log law   $log_a(b)=c \implies a^c=b$:

$x=10^{\frac14(y-5)}$

Answer 2

$\\ \tt\hookrightarrow 4logx+5=y$

$\\ \tt\hookrightarrow 4logx=y-5$

$\\ \tt\hookrightarrow logx=\dfrac{y-5}{4}$

$\\ \tt\hookrightarrow x=10^{\dfrac{y-5}{4}}$

$\\ \tt\hookrightarrow x=\sqrt[4]{10^{y-5}}$