This problem is asking for the required heat to change the temperature of 500 g of water by 50 °C. At the end, the result turns out to be 25,000 cal as shown below:
Calorimetry
In science, calorimetry is the process whereby objects lose or gain energy according to the decrease or increase of their temperature. Thus, for these problems, we need to use the following equation:
[tex]Q =mC(T_f-T_i)[/tex]
Where Q stands for the heat, m for the mass, C for the specific heat of the object and T for the temperature (final and initial). Thus, for this problem, since it is about water, one fixes its specific heat as 1 cal /(g-°C) in order to obtain the following:
[tex]Q=500g*1\frac{1cal}{g\°C} *50\°C\\\\Q=25,000cal[/tex]
Learn more about calorimetry: brainly.com/question/1407669
