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D satisfies the lines [tex]y=3x-2[/tex] and [tex]y=-2x+3[/tex] where they intersect each other.
Given equations:
y = 3x - 2
y = -2x + 3
solve for x:
3x - 2 = -2x + 3
3x + 2x = 3 + 2
5x = 5
x = 1
solve for y:
y = 3x - 2
y = 3(1) - 2
y = 3 - 2
y = 1
coordinates where these lines satisfies area: ( 1 , 1)
Answer:
D (1, 1)
Step-by-step explanation:
y = 3x - 2
y = -2x + 3
The solution is the point of intersection.
To find the point of intersection, equate the equations and solve for x, then substitute found value of x into one of the equations and solve for y:
y = y
⇒ 3x - 2 = -2x + 3
⇒ 5x = 5
⇒ x = 1
when x = 1: y = 3(1) - 2 = 1
Therefore point of intersection is (1, 1)