The expected value of a distribution is the mean of the distribution
The number of tosses is 62
The expected value is given as:
E(x) = 35
The probability is given as:
p = 9/16
So, we have:
E(x) = n * p
Substitute known values
[tex]35 = n * 9/16[/tex]
Divide both sides by 9/16
n = 62
Hence, the number of tosses is 62
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