Respuesta :

Answer:

2 irrational solutions

Step-by-step explanation:

using the quadratic formula:

[tex] \frac{ -b \:± \sqrt{b {}^{2} - 4ac } }{2a} [/tex]

3x²−x−5=0

where a = 3, b = -1 and c = -5, plug in those values in the quadratic formula

[tex] \frac{ - ( - 1)±\sqrt{(1) {}^{2} - 4(3)( - 5) } }{2(3)} [/tex]

you get two solutions:

[tex] \frac{1 + \sqrt{61} }{6} \: and \: \frac{1 - \sqrt{61} }{6} [/tex]

both can be written as:

[tex] \frac{1± \sqrt{61} }{6} [/tex]

They are irrational as they cannot be written in the form p/q where p and q are whole numbers (integers)