Question

2 moles of a gas have a pressure of 2 atm at a temperature of 300 K. What is the volume of the gas?

Answer 1

• No of moles=2mol=n
• Pressure=2atm=P
• Temperature=300K=T
• Volume=V

$\\ \tt\hookrightarrow PV=nRT$

$\\ \tt\hookrightarrow V=\dfrac{nRT}{P}$

$\\ \tt\hookrightarrow V=\dfrac{2(8.314)(300)}{2}$

$\\ \tt\hookrightarrow V=8.314(300)$

$\\ \tt\hookrightarrow V=2494.2mL$

$\\ \tt\hookrightarrow V=24.94dm^3$

Answer 2

2 moles of a gas have a pressure of 2 atm at a temperature of 300 K then volume will be 24.94 $dm^{3}$.

What are moles?

The mole would be a SI unit that is used to quantify the quantity of any material. Mol is just the shorthand for "mole."

What is pressure?

The force among all gas particle/wall interactions distributed mostly by the surface area of the wall would be the definition of pressure (P). Another of the fundamental quantifiable variables of this stage of matter, pressure, would be a property shared by all gases.

Calculation of volume.

Given data:

Number of moles = 2 mol

pressure = 2 atm

Temperature = 300K

Volume = ?

Volume can be calculated by using the formula:

PV = nRT

where, P is pressure, T is temperature.

Now, put the value of given data in above equation.

V = nRT / P

V = 2 × 8.31× 300/ 2

V = 2494.2ml

V = 24.94 $dm^{3}$

Therefore, the volume will be 24.94 $dm^{3}$

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