Using the normal distribution, it is found that the area of the shaded region is of 0.8238.
Normal Probability Distribution
In a normal distribution with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the z-score of a measure X is given by:
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
- It measures how many standard deviations the measure is from the mean.
- After finding the z-score, we look at the z-score table and find the p-value associated with this z-score, which is the percentile of X.
In this problem:
- The mean is of [tex]\mu = 100[/tex].
- The standard deviation is of [tex]\sigma = 15[/tex].
- The area of the shaded region is 1 subtracted by the p-value of Z when X = 86.
Hence:
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
[tex]Z = \frac{86 - 100}{15}[/tex]
[tex]Z = -0.93[/tex]
[tex]Z = -0.93[/tex] has a p-value of 0.1762.
1 - 0.1762 = 0.8238.
The area of the shaded region is of 0.8238.
More can be learned about the normal distribution at https://brainly.com/question/24663213