Answer:
Use the data from the caliper method and determine the cube's volume.Cube's volume = (0.85 cm)3 = 0.85 cm × 0.85 cm × 0.85 cm = 0.6141 cm3 (unrounded)= 0.61 cm3 (rounded)Calculate the density. Note that extra digits were brought into this step of the calculation.Cube's density = 0.66 g0.6141 cm3 = 1.1 gcm3Recall that 1 cm3 = 1 mL, so that density is 1.1 g/mL.Liquid Displacement MethodUse the mass and change in volume from the collected data to calculate the density.Cube's density = 0.66 g(6.2 − 5.5) mL = 0.9 gmLSuspension MethodWhen the cube is suspended in a liquid, the density of the cube is equal to the density of the liquid.Use the volume of each liquid and its associated density to determine the total mass and total volume of the solution mixture.Total volume = (7.5 + 4.8) mL = 12.3 mLTotal mass = (7.5 mL × 0.789 g/mL) + (4.8 mL × 1.259 g/mL) = 11.9607 g (unrounded)= 12.0 g (rounded)
Then calculate the cube's density.Cube's density = Mixture's density = 11.9607 g12.3 mL = 0.972 gmLPercent error = │experimental value − true value│true value × 100Caliper Method Percent Error = 12%Liquid Displacement Percent Error = 8%Suspension Method Percent Error = 1.0%The suspension method is most accurate.
