Answer:
[tex]20x^8y^{10}[/tex]
Step-by-step explanation:
[tex]\frac{4x^{-2}y^2}{2^{-3}x^2y^7}*(x^{-4}y^{-5})^{-3}-12x^8y^{10}[/tex]
you have to cancel the fraction stuff, distribute the exponent in the second term multiply, simplify like terms and then subtract the last term
it would take a very long time for me to explain all this and type it out so instead copy and paste this into mathpapa.com and it will explain it
\frac{4x^{-2}y^2}{2^{-3}x^2y^7}*(x^{-4}y^{-5})^{-3}-12x^8y^{10}
then let me know if you have any questions in the comments and I will answer
Hope this helps! :)
