Question

find g(-1) if g(x)=x^3+3x^2+3x+1​

Answer 1

Option (c) $0.$

Step-by-step explanation:

Put x = -1 Then,

$g( - 1) = {( - 1)}^{3} + 3 {( - 1)}^{2} + 3( - 1) + 1$

$g( - 1) = - 1 + 3 - 3 + 1$

Here, -1 , +1 gets cancelled and +3 , -3 gets cancelled. Hence,

$g( - 1) = 0.$

Answer 2

Answer:

g-1 =0

Step-by-step explanation:

x+1 is factor then f(−1)=0

Replace x in p(x) by −1 we get

f(x)=x

3

+3x

2

+3x+1

or,f(−1)=(−1)

3

+3(−1)

2

+3(−1)+1

or,f(−1)=−1+3−3+1

or,f(−1)=0