The angle ∠EJS is bisected by the diagonal JS to form an angle of 62°
Response:
Properties of a rhombus:
The lengths of the sides of a rhombus are equal
The measure of the opposite angles of a rhombus are equal
The diagonals bisect the interior angles of a rhombus
Given that JOSE is a rhombus, and ∠ESO = 124°, we have;
∠EJO = ∠ESO = 124° opposite angles of a rhombus
∠EJS = ∠OJS definition of bisected angle ∠EJO
∠EJS + ∠OJS = ∠EJO by angle addition
[tex]\angle EJS = \dfrac{124^{\circ}}{2} = \mathbf{62^{\circ}}[/tex]
Learn more about a rhombus here:
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