Question

Nitrogen (N2) and hydrogen (H2) react to make NH3 according to the following
chemical equation:
N2 (g) + 3 H2(g) + 2NH3 (g)
If 0.50 moles of N2 and 0.75 moles of H2 are allowed to react, how many moles
of NH3 could you make? Enter your unrounded ar/swer.

Answer 1

The number of moles of NH3 that could be made would be 0.5 moles

Stoichiometric reactions

From the balanced equation of the reaction:

N2 (g) + 3 H2(g) ----> 2NH3 (g)

The mole ratio of N2 to H2 is 1:3

Thus, for 0.50 moles of N2, 1.5 moles of H2 should be present. But 0.75 moles of H2 was allowed to react. Meaning that H2 is limiting in this case.

Mole ratio of H2 and NH3 = 3:2

Thus for 0.75 moles H2, the mole of NH3 that would be produced will be:

                       2 x 0.75/3 = 0.5 moles

More on stoichiometric calculations can be found here: https://brainly.com/question/8062886