Question

Germanium and chlorine react according to the following chemical equation:
Ge (s) + 2Cl2 (g) →→GeCl4 (1)
If 1.0 g of Ge and 1.0 Cl2 are allowed to react, what mass (in g) of GeCl4 could
be formed? Save your rounding until the end, and enter your answer to at least
two significant figures.

Answer 1

The mass of GeCl4 that would be formed will be 1.51 g

Stoichiometric calculations

From the balanced equation of the reaction:

Ge (s) + 2Cl2 (g) →GeCl4

The mole ratio of Ge and Cl2 is 1:2.

Mole of 1.0 g Ge: 1/72.64

                               = 0.01377 mole

Mole of 1.0 g Cl2 = 1/71

                             = 0.01408 mole

Thus, Cl2 is limiting.

Mole ratio of Cl2 and GeCl4 = 2:1

Equivalent mole of GeCl4 = 0.01408/2

                                       = 0.0070 mole

Mass of 0.0070 mole GeCl4 = 0.0070 x 214.4

                                               = 1.51 g

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