Question

Feb 03, 11:54:47 PM

Solve for the value of n.
(n+6°
(2n+3)
Bu
Answer: n =
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attempt 1 out of 2

Answer 1

I could be wrong here

n+6=2n+3

Subtract n from n+6 and subtract n from 2n+3 to get 6=n+3

Subtract 3 from both sides to end up with n = 3

?

Answer 2

I think you make the whole equation = 180. So 2n+3 + n + 6=180
3n +9=180
3n=171 then divide by 3 =57
N=57