Question

A sample of argon gas is cooled and its volume went from 380 mL to 250 20 points
ml. If its final temperature was -55°C, what was its original temperature?

Answer 1

Answer:

Applying the Laws of Thermodynamics we get as,

Explanation:

V1/T1 = V2/T2

According to the law of Gaseous states.

so we get as,

V1 = 380 ml, V2 = 250 ml, T2 = -55°C ==> 273-55 ==> 218 Kelvin.

so now substituting we get as,

380/ T1 =250/218

==> 380*(218) /250 = T1

==> T1 = 331.36 ===>T1 = 331 K approx

So the Original Temperature was 331 K,

Option 1.) is correct.