Answer:
You have a 2.0 L balloon filled with air at a temperature of 273 K.
When the volume of the balloon increases to 2.4 L, what is the new temperature?
240 K
323 K
655 K
900 K
Apply Charles law
[tex]\\ \rm\Rrightarrow V_1T_2=V_2T_1[/tex]
[tex]\\ \rm\Rrightarrow 2T_2=2.4(273)[/tex]
[tex]\\ \rm\Rrightarrow 2T_2=655.2[/tex]
[tex]\\ \rm\Rrightarrow T_2=\dfrac{655.2}{2}[/tex]
[tex]\\ \rm\Rrightarrow T_2=327.6K[/tex]