If Ej bisects ZH&J, solve for z.
A. X= 41
B. X=47
C. X= 48
D. X= 49
![If Ej bisects ZHampJ solve for z A X 41 B X47 C X 48 D X 49 class=](https://us-static.z-dn.net/files/d02/86f0c300802c7229067b0c61d4ffbeb4.png)
Answer:
x = 47
Step-by-step explanation:
Bisect means split in half.
If El bisects ∠HEJ then the angles that are created from the bisected segment are congruent
Hence, ∠HEl = ∠JEI
If ∠HEl = x + 3 and ∠JEl = 3x - 91
and the two are congruent
then x + 3 = 3x - 91
Note that we've just created an equation that we can use to solve for x
we now solve for x
x + 3 = 3x - 91
add 91 to both sides
x + 3 + 91 = 3x - 91 + 91
x + 94 = 3x
subtract x from both sides
x - x + 94 = 3x - x
94 = 2x
divide both sides by 2
94/2 = 47
2x/2=x
we're left with x = 47