The solution to the system of equation is (-3/2, 0) and (-1, 1)
Graphs and functions
Given the functions
y = 2x^2 + x
y = 2x + 3
Equation both equatons
2x^2 + x = 2x + 3
2x^2 + x - 2x - 3 = 0
2x^2 - x - 3 = 0
Factorize the function
2x^2 - 2x + 3x - 3 = 0
2x(x-1) + 3(x-1) = 0
x - 1 = 0 and 2x + 3 = 0
x = 1 and -3/2
If x = -1, y = 2x + 3
y = 2(-1) + 3
y = -2 + 3
y = 1
Hence if x = -1, y = 1
If x = -3/2
y = 2(-3/2) + 3
y = -3 + 3
y = 0
Hence the other solution is (-3/2, 0)
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