The number of police officers in 2016 to have a greater percent increase than that of private investigators will be 761,307.
Given:
Private investigators in 2006 = 52,000
Private investigators in 2016 = 61,000
The percentage increase in the number of private investigators can be calculated as:
[tex]\begin{aligned} \rm Percentage\:increase\ &= \dfrac{Increase\:in\:Private \:investigators\:from\:2006\:2016}{Private\: investigators\:in\:2006}\times 100\\\\&= \dfrac{61,000 - 52,000}{52,000}\times 100\\\\&=\dfrac{9,000}{52,000}\times 100\\\\&= 17.30\% \end[/tex]
The increased number of police officers can be calculated as;
[tex]\begin{aligned} \rm Police\:officers\:in\:2016 &= Police\:officers\:in\:2006 + 17.30\%\\\\&= 648,982 + 17.30\%\\\\&= 761255.886\end[/tex]
Since the percentage increase in the number of officers is more than that of private investigators. The number of police officers will be 761,307.
Hence the correct option is b.
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