Question

One end of an elastic cord is fastened to a steel beam. A
mass
metal weight will a mass of 68 kg is attached to the other
end of the cord and dropped from the level of the beam. The
traveling
weight is traveling
at 14 m/s downward when the rest of the
cord is exceeded and the cord begins to Stretch and exert an
upward force on the metal weight. After 0.85 seconds, the weight is
moving an upward with a speed of limis. What is the average
force on the weight during this time period?

Answer 1

The average force on the weight during the time period is 1120 N

Data obtained from the question

From the question given above, the following data were obtained:

• Mass (m) = 68 Kg
• Velocity (v) = 14 m/s
• Time (t) = 0.85 s

• Force (F) =?

Determination of the acceleration

• Mass (m) = 68 Kg
• Velocity (v) = 14 m/s
• Time (t) = 0.85 s

• Acceleration (a) =?

a = v / t

a = 14 / 0.85

a = 16.47 m/s²

How to determine the force

• Mass (m) = 68 Kg
• Acceleration (a) = 16.47 m/s²

• Force (F) =?

The force can be obtained as follow:

F = ma

F = 68 × 16.47

F = 1119.96 N

F ≈ 1120 N

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