Question

A student prepares 150. 0 mL of 1. 40 M HCl using 35. 0 mL of a stock solution. What is the concentration of the stock solution? Use M subscript i V subscript i equals M subscript f V subscript f. 0. 327 M 4. 29 M 6. 00 M 7. 35 M.

Answer 1

6.00 M is the concentration of the stock solution.

Molarity or the molar concentration is the measure of the chemical species amount of solute in the solvent or the solution. The molarity of the solute is given by the moles and the volume in which it is dissolved.

How to calculate the concentration of the stock solution?

Given,

• The molar concentration of $\rm HCl$ $(\rm M_{1})$ =  1.40 M
• The volume of hydrochloric acid $(\rm V_{1})$ = 150.0 mL
• The molar concentration of stock solution = ?
• The volume of stock solution $(\rm V_{2})$ = 35.0 mL

The molarity can be estimated by:

$\rm M_{1}V_{1} = M_{2}V_{2}$

Substituting values in the formula:

$\begin{aligned}1.40 \;\rm M \times 150.0 \;\rm mL &= \;\rm M_{2} \times 35.0 \;\rm mL\\\\\rm M_{2} &= \dfrac{210}{35}\\\\&= 6 \;\rm M\end{aligned}$

Therefore, 6.00 M is the concentration of the stock solution.

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