First you would use n=cv(moles= concentration x volume) to find the moles so you would do 1.00M which is the concentration x 1litre which would = 1 mol Then you would use the mass=moles x mR triangle to give you the mass needed So your moles are 1 which you found out and your mR is Na (23.0) add Cl (35.5) so mR of NaCl is 58.5 So 58.5 x 1 = 58.5 You would need 58.5 grams
