Question

Find area of isosceles triangle 13cm 10cm

Answer 1

Answer:

65 cm^2 or centimeter squared

Step-by-step explanation:

area of a triangle is

1/2 * b * h

1/2 * 13 * 10

65

Answer 2

Answer:

The area of isosceles triangle is 65 cm².

Step-by-step explanation:

SOLUTION :

Here's the required formula to find the area of Isosceles triangle :

$\longrightarrow{\pmb{\sf{A = \dfrac{1}{2} bh}}}$

• A = Area
• b = base
• h = height

Substituting all the given values in the formula to find the area of Isosceles triangle :

$\implies{\sf{A_{(\triangle)} = \dfrac{1}{2} bh}}$

$\implies{\sf{A_{(\triangle)} = \dfrac{1}{2} \times b \times h}}$

$\implies{\sf{A_{(\triangle)} = \dfrac{1}{2} \times 13 \times 10}}$

$\implies{\sf{A_{(\triangle)} = \dfrac{1}{\cancel{2}} \times 13 \times \cancel{10}}}$

$\implies{\sf{A_{(\triangle)} = 1 \times 13 \times 5}}$

$\implies{\sf{A_{(\triangle)} = 13 \times 5}}$

$\implies{\sf{A_{(\triangle)} = 65}}$

$\star{\boxed{\sf{\red{A_{(\triangle)} = 65 \: {cm}^{2}}}}}$

Hence, the area of isosceles triangle is 65 cm².

$\rule{200}2$

LEARN MORE :

$\begin{gathered}\begin{gathered}\begin{gathered}\begin{gathered}\begin{gathered}\boxed{\begin{minipage}{9cm}\\ \dag\quad \Large\underline{\bf Formulas\:of\:Triangle:-}\\ \\ \star\sf Triangle \:area = \dfrac{1}{2}\times b \times h\\ \\ \star\sf Triangle \: perimeter=a+b+c\\\\ \star\sf Scalene\:\triangle=\sqrt{s (s-a)(s-b)(s-c)}\\\\\star\sf Equilateral\: \triangle\:area = \dfrac{\sqrt{3}}{4}\times{side}^{2}\\\\\star\sf Equilateral \:\triangle\:perimeter = 3 \times side\\\\\star\sf Isosceles\: \triangle\:area= \dfrac{3}{4}\sqrt{{4b}^{2}-{a}^{2}}\\\\\star\sf Isosceles\:\triangle\:perimeter=a+2b\end{minipage}}\end{gathered}\end{gathered}\end{gathered}\end{gathered}\end{gathered}$

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