This problem is providing us with the width, 14.15 inches and height, 10.61 inches of a computer monitor, so the area of this display in square meters is required. At the end, the result turns out to be 0.09659 m².
In chemistry, we use dimensional analysis in order to figure out results given some numerical information; however, despite not having a specific formula for every problem, one can use the required units as a reference to come up with a convenient mathematical setup.
In this case, one can firstly calculate the area in square inches:
[tex]A=14.15in*10.61in\\\\A=150.1in^2[/tex]
Next, we use the equivalence statement relating inches with meters, 1 in = 0.0254 m, to obtain:
[tex]A=150.1in^2*(\frac{0.0254m}{1in} )^2\\\\A=0.09659m^2[/tex]
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